(-2x^2+10x+100)/(x+5)^2=0

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Solution for (-2x^2+10x+100)/(x+5)^2=0 equation: 


D( x )

(x+5)^2 = 0

(x+5)^2 = 0

(x+5)^2 = 0

x+5 = 0 // - 5

x = -5

x in (-oo:-5) U (-5:+oo)

(10*x-2*x^2+100)/((x+5)^2) = 0

10*x-2*x^2+100 = 0

2*(5*x-x^2+50) = 0

5*x-x^2+50 = 0

DELTA = 5^2-(-1*4*50)

DELTA = 225

DELTA > 0

x = (225^(1/2)-5)/(-1*2) or x = (-225^(1/2)-5)/(-1*2)

x = -5 or x = 10

2*(x+5)*(x-10) = 0

(2*(x-10))/(x+5) = 0

x-10 = 0 // + 10

x = 10

x = 10

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